Matematika Sekolah Menengah Atas tolong bantu aku dong plisss kak aku mau dikumpulin soalnya ​

tolong bantu aku dong plisss kak aku mau dikumpulin soalnya ​

7π/6 = 7π/6×180/π = 1190/6= 193,3 (edit yang D)

jangan lupa follow dan jadikan jawaban terbaik, terimakasih

Jawaban:

1.

a.

[tex] \frac{4}{9} \pi[/tex]

b.

[tex] \frac{7}{10} \pi[/tex]

c. 225°

d. 210°

2. 24/13

3. 120/169

4.

[tex] \frac{5}{6} \sqrt{3} + \frac{1}{2} \sqrt{2} [/tex]

Penjelasan dengan langkah-langkah:

1.

a.

[tex] \frac{80}{180} \\ = \frac{8}{18} \\ = \frac{4}{9} \pi[/tex]

b.

[tex] \frac{126}{180} \\ = \frac{21}{30} \\ = \frac{7}{10} \pi[/tex]

c.

[tex] \frac{5}{4} \pi \\ = \frac{5}{4} \times 180 \\ = 5 \times 45 \\ = 225[/tex]

= 225°

d.

[tex] \frac{7}{6} \pi \\ = \frac{7}{6} \times 180 \\ = 7 \times 30 \\ = 210[/tex]

210°

2.

[tex] {sin}^{2} \alpha + \cos {}^{2} ( \alpha ) = 1 \\ {sin}^{2} a + ( \frac{5}{13} ) {}^{2} = 1 \\ {sin}^{2} \alpha + \frac{25}{169} = 1 \\ {sin}^{2} \alpha = \frac{144}{169} \\ \sin( \alpha ) = \frac{12}{13} \\ 2 \sin(a) = \frac{24}{13} [/tex]

3.

sin a= 12/13

sin²a+cos²a= 1

(12/13)+cos²a= 1

144/169+cos²a= 1

cos²a= 25/169

cos a= 5/13

2 sin a cos a

= 2(12/13)(5/13)

= 120/169

4.

[tex] \sin(60) + \tan(30) + \cos(45) \\ = \frac{1}{2} \sqrt{3} + \frac{1}{3} \sqrt{3} + \frac{1}{2} \sqrt{2} \\ = \frac{5}{6} \sqrt{3} + \frac{1}{2} \sqrt{2} [/tex]

[answer.2.content]